Note: The properties of the particular hexagon below are additional to those given at
Converse of Theorem 1
The alternative formulation of theorem 1 now gives us the following neat converse: Given a hexagon ABCDEF with AB = BC, CD = DE, EF = FA, and the angle bisectors of ∠A, ∠C, and ∠E are concurrent at the circumcentre, Q, of △ACE, then ∠A = ∠C = ∠E.
Theorem 2
Given a hexagon ABCDEF with AB = BC, CD = DE, EF = FA, and ∠A = ∠C = ∠E, then ABCDEF is cyclic only when △ACE is equilateral, and the hexagon is regular.
Click on the Link to Cyclic Exploration button below to dynamically explore this theorem with an interactive sketch.
Additional properties of a particular hexagon
Challenge
Can you prove Theorem 1 and its converse, as well as Theorem 2?
Further Generalization
Can you generalize Theorem 1 and its converse to an octagon, decagon, etc.?
1) Click on the Link to Octagon by reflection to explore a generalization of the converse of Theorem 1 to an octagon,
2) Click on the Link to Octagon Check buttons to check whether Theorem 1 similarly generalizes to an octagon. What do you notice?
3) Click on the Link to Decagon to explore a generalization of both Theorem 1 and its converse to a decagon.
Challenge: Can you prove the generalizations above?
Reference
De Villiers, M. (2022).
More Properties of this Particular Hexagon
Created by Michael de Villiers, 24 September 2022 with WebSketchpad, updated 26 September 2022, 12 March 2023.