Logical explanations of rhombus properties
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1)
Equal sides
Under a reflection around the axis of symmetry x, side AB maps to side
, and side BC maps to side
. Hence, side AB = side
and side BC = side
. Similarly, by reflection around the axis of symmetry
it follows that
= CB and
= DC. By the
property it therefore follows that AB = BC = CD = DA; i.e. all sides are equal.
2)
Perpendicular diagonals
A reflection of triangle ABI around the axis of symmetry x maps it to triangle
. Since diagonal BD, which lies on y, is a straight line, it follows that adjacent angles AIB and
are 90 degrees. Similarly, from a
around line y it follows that angle AIB = 90 = angle
.
3)
Bisected opposite angles
A reflection of angle BAC around the axis of symmetry x maps it to angle
. Hence, diagonal AC
angle BAD. In the same, it follows that the other angles are bisected by the diagonals.
4)
Circumscribed
The line of symmetry x is the
bisector of both angles BAD and BCD, and so is line
of angles ABC and CDA. Since, an angle bisector is the path of all points equi-distant from the
forming the angle it bisects, it follows that since all 4 angle bisectors are concurrent at I, that I is
from sides AB, BC, CD and DA. Hence, a circle can be drawn with I as
and one of the four equal
distances to the four sides as the radius.
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